# Line slope calculator x-5y=-9

**Straight line given by points A[1; 2] and B[6; 3]**

## Calculation:

**Slope-intercept form of line:**y = 0.2x+1.8

**Canonical form of the line equation:**x-5y+9 = 0

**Parametric form of the line equation:**

x = 5t+1

y = t+2 ; t ∈ R

**Slope:**m = 0.2

**Slope angle of line: φ =**11°18'36″ = 0.1974 rad

**X intercept:**x

_{0}= -9

**Y intercept:**y

_{0}= q = 1.8

**Distance line from the origin:**d

_{0}= 1.765

**The length of the segment AB: |AB| =**5.099

**Vector: AB =**(5; 1)

**Normal vector: n =**(1; -5)

**Midpoint of the segment AB: M =**[3.5; 2.5]

**Perpendicular Bisector equation:**5x+y-20 = 0

**Vector OA = (1; 2) ; |OA| = 2.2361**

**Vector OB = (6; 3) ; |OB| = 6.7082**

**Scalar product OA .OB = 12**

**Angle ∠ AOB = 36°52'12″ = 0.6435 rad**