# Line slope calculator 4x+5y=46

**Straight line given by points A[4; 6] and B[9; 2]**

## Calculation:

**Slope-intercept form of line:**y = -0.8x+9.2

**Canonical form of the line equation:**4x+5y-46 = 0

**Parametric form of the line equation:**

x = 5t+4

y = -4t+6 ; t ∈ R

**Slope:**m = -0.8

**Slope angle of line: φ =**-38°39'35″ = -0.6747 rad

**X intercept:**x

_{0}= 11.5

**Y intercept:**y

_{0}= q = 9.2

**Distance line from the origin:**d

_{0}= 7.184

**The length of the segment AB: |AB| =**6.4031

**Vector: AB =**(5; -4)

**Normal vector: n =**(4; 5)

**Midpoint of the segment AB: M =**[6.5; 4]

**Perpendicular Bisector equation:**5x-4y-16.5 = 0

**Vector OA = (4; 6) ; |OA| = 7.2111**

**Vector OB = (9; 2) ; |OB| = 9.2195**

**Scalar product OA .OB = 48**

**Angle ∠ AOB = 43°46'52″ = 0.7641 rad**