# Median after K additional integers

Given an array of n integers. We are allowed to add k additional integer in the array and then find the median of the resultant array. We can choose any k values to be added. **Constraints: **

k < n n + k is always odd.

**Examples : **

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Input : arr[] = { 4, 7 } k = 1 Output : 7 Explanation : One of the possible solutions is to add 8 making the array [4, 7, 8], whose median is 7 Input : arr[] = { 6, 1, 1, 1, 1 } k = 2 Output : 1 Explanation : No matter what elements we add to this array, the median will always be 1

We first sort the array in increasing order. Since value of k is less than n and n+k is always odd, we can always choose to add k elements that are greater than the largest element of an array, and (n+k)/2th element is always a median of the array.

## C++

`// CPP program to find median of an array when` `// we are allowed to add additional K integers` `// to it.` `#include <bits/stdc++.h>` `using` `namespace` `std;` `// Find median of array after adding k elements` `void` `printMedian(` `int` `arr[], ` `int` `n, ` `int` `K)` `{` ` ` `// sorting the array in increasing order.` ` ` `sort(arr, arr + n);` ` ` `// printing the median of array.` ` ` `// Since n + K is always odd and K < n,` ` ` `// so median of array always lies in` ` ` `// the range of n.` ` ` `cout << arr[(n + K) / 2];` `}` `// driver function` `int` `main()` `{` ` ` `int` `arr[] = { 5, 3, 2, 8 };` ` ` `int` `k = 3;` ` ` `int` `n = ` `sizeof` `(arr) / ` `sizeof` `(arr[0]);` ` ` `printMedian(arr, n, k);` ` ` `return` `0;` `}` |

## Java

`// Java program to find median of an array when` `// we are allowed to add additional K integers` `// to it.` `import` `java.util.Arrays;` `class` `GFG {` ` ` ` ` `// Find median of array after adding k elements` ` ` `static` `void` `printMedian(` `int` `arr[], ` `int` `n, ` `int` `K)` ` ` `{` ` ` ` ` `// sorting the array in increasing order.` ` ` `Arrays.sort(arr);` ` ` ` ` `// printing the median of array.` ` ` `// Since n + K is always odd and K < n,` ` ` `// so median of array always lies in` ` ` `// the range of n.` ` ` `System.out.print(arr[(n + K) / ` `2` `]);` ` ` `}` ` ` ` ` `//Driver code` ` ` `public` `static` `void` `main (String[] args)` ` ` `{` ` ` ` ` `int` `arr[] = { ` `5` `, ` `3` `, ` `2` `, ` `8` `};` ` ` `int` `k = ` `3` `;` ` ` `int` `n = arr.length;` ` ` ` ` `printMedian(arr, n, k);` ` ` `}` `}` `// This code is contributed by Anant Agarwal.` |

## Python3

`# Python3 code to find median of an` `# array when we are allowed to add` `# additional K integers to it.` `# Find median of array after` `# adding k elements` `def` `printMedian (arr, n, K):` ` ` ` ` `# sorting the array in` ` ` `# increasing order.` ` ` `arr.sort()` ` ` ` ` `# printing the median of array.` ` ` `# Since n + K is always odd` ` ` `# and K < n, so median of` ` ` `# array always lies in` ` ` `# the range of n.` ` ` `print` `( arr[` `int` `((n ` `+` `K) ` `/` `2` `)])` `# driver function` `arr ` `=` `[ ` `5` `, ` `3` `, ` `2` `, ` `8` `]` `k ` `=` `3` `n ` `=` `len` `(arr)` `printMedian(arr, n, k)` `# This code is contributed by "Sharad_Bhardwaj".` |

## C#

`// C# program to find median of an array when` `// we are allowed to add additional K integers` `// to it.` `using` `System;` `class` `GFG` `{` ` ` `// Find median of array after adding k elements` ` ` `static` `void` `printMedian(` `int` `[]arr, ` `int` `n, ` `int` `K)` ` ` `{` ` ` `// sorting the array in increasing order.` ` ` `Array.Sort(arr);` ` ` ` ` `// printing the median of array.` ` ` `// Since n + K is always odd and K < n,` ` ` `// so median of array always lies in` ` ` `// the range of n.` ` ` `Console.Write(arr[(n + K) / 2]);` ` ` `}` ` ` ` ` `//Driver code` ` ` `public` `static` `void` `Main ()` ` ` `{` ` ` `int` `[]arr = { 5, 3, 2, 8 };` ` ` `int` `k = 3;` ` ` `int` `n = arr.Length;` ` ` `printMedian(arr, n, k);` ` ` `}` `}` `// This code is contributed by anant321.` |

## PHP

`<?php` `// PHP program to find median` `// of an array when we are allowed` `// to add additional K integers to it.` `// Find median of array` `// after adding k elements` `function` `printMedian(` `$arr` `, ` `$n` `, ` `$K` `)` `{` ` ` `// sorting the array` ` ` `// in increasing order.` ` ` `sort(` `$arr` `);` ` ` `// printing the median of` ` ` `// array. Since n + K is` ` ` `// always odd and K < n,` ` ` `// so median of array always` ` ` `// lies in the range of n.` ` ` `echo` `$arr` `[(` `$n` `+ ` `$K` `) / 2];` `}` `// Driver Code` `$arr` `= ` `array` `( 5, 3, 2, 8 );` `$k` `= 3;` `$n` `= ` `count` `(` `$arr` `);` `printMedian(` `$arr` `, ` `$n` `, ` `$k` `);` `// This code is contributed by Sam007` `?>` |

## Javascript

`<script>` `// Javascript program to find median of an array when` `// we are allowed to add additional K integers` `// to it.` ` ` `// Find median of array after adding k elements` ` ` `function` `printMedian(arr, n, K)` ` ` `{` ` ` ` ` `// sorting the array in increasing order.` ` ` `arr.sort();` ` ` ` ` `// printing the median of array.` ` ` `// Since n + K is always odd and K < n,` ` ` `// so median of array always lies in` ` ` `// the range of n.` ` ` `document.write(arr[Math.floor((n + K) / 2)]);` ` ` `}` `// driver program` ` ` `let arr = [ 5, 3, 2, 8 ];` ` ` `let k = 3;` ` ` `let n = arr.length;` ` ` ` ` `printMedian(arr, n, k);` ` ` `</script>` |

**Output :**

8

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