#### PhantomT828

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I tried making the equation 3^(4x) - 3^(1 + 2x) + 2 = 0 , then converting it to a logarithm but I was unable to get an answer.

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- Thread starter PhantomT828
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- Joined
- Oct 13, 2021

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I tried making the equation 3^(4x) - 3^(1 + 2x) + 2 = 0 , then converting it to a logarithm but I was unable to get an answer.

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Hi Phantom. Writing 3^(4x) is good. You could also factor the power 3^(1+2x), to help see the quadratic3^(4x) - 3^(1 + 2x) + 2

3^(1 + 2x) = 3^1 * 3^(2x) = 3*3^(2x)

Let us know how it goes.

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Consider [imath] 9^{2x} - 3^{1 + 2x} + 2 = 3x^{4x}-3\cdot 3^{2x}+2=0[/imath]. Now use [imath]y=3^{2x}[/imath].

I tried making the equation 3^(4x) - 3^(1 + 2x) + 2 = 0 , then converting it to a logarithm but I was unable to get an answer.

[imath]y^2-3y+2=(y-2)(y-1)=0[/imath]

Can